discretize.tests.OrderTest.assertCountEqual

OrderTest.assertCountEqual(first, second, msg=None)[source]

Asserts that two iterables have the same elements, the same number of times, without regard to order.

self.assertEqual(Counter(list(first)),

Counter(list(second)))

Example:
  • [0, 1, 1] and [1, 0, 1] compare equal.

  • [0, 0, 1] and [0, 1] compare unequal.