discretize.tests.OrderTest.assertCountEqual#
- OrderTest.assertCountEqual(first, second, msg=None)[source]#
Asserts that two iterables have the same elements, the same number of times, without regard to order.
- self.assertEqual(Counter(list(first)),
Counter(list(second)))
- Example:
[0, 1, 1] and [1, 0, 1] compare equal.
[0, 0, 1] and [0, 1] compare unequal.